Matematika

Pertanyaan

faktor aljabar
3x-3y=
2x+6=
x³+xy²=
ap²+2ap=
4x²y-6xy³=

2 Jawaban

  • 3x - 3y = 3(x-y)
    2x + 6 = 2(x+3)
    [tex] x^{3} +x y^{2} =x ( x^{2} + y^{2} )[/tex]
    [tex]a p^{2} +2ap = ap (p+2)[/tex]
    [tex]4 x^{2} y-6x y^{3} = 2xy (2x-3 y^{2} )[/tex]
  • 3x-3y = 3(x-y)
    2x+6 = 2(x+3)
    x³+xy² = x(x²+y²)
    ap²+2ap = ap(p+2)
    4x²y-6xy³ = 2xy(2x-3y)

    insyaAllah bener.

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