tentukan persamaan garis s yg melalui titik (1,3) dan sejajar dgn garis -x +3y+2 = 0

3y = x - 2
y = (1/3)x - 2/3
m = 1/3

Persamaan garis
y - b = m(x - a)
y - 3 = (1/3)(x - 1)
3y - 9 = x - 1
x - 3y + 8 = 0

[tex]-x+3y+2=0[/tex]
[tex]3y=x-2[/tex]
[tex]y= \frac{1}{3} x- \frac{2}{3} [/tex]
[tex]gradien=m=\frac{1}{3} [/tex]
[tex]y-3 =\frac{1}{3}(x-1)[/tex]
[tex]y-3 -\frac{1}{3}x+\frac{1}{3}=0[/tex]
[tex]3y-x-8=0[/tex]