tentukan hasil integral tentu. sekarang juga ya jawabannya

Integral Tentu Fungsi Trigonometri.

[tex]\displaystyle \int_{\pi /4}^{\pi /2}\left ( \cos x-\frac{\pi }{2} \right )dx=\int_{\pi /4}^{\pi /2}\sin x~dx\\ =\left [ -\cos x \right ]_{\pi /4}^{\pi /2}\\ =-\cos \frac{\pi}{2}-\left ( -\cos \frac{\pi}{4} \right )=0+\frac{\sqrt{2}}{2}=\frac{\sqrt{2}}{2}[/tex]