tentukan nilai bentuk aljabar berikut jika nilai x = 16 dan y = 64a. (2x)¹/5b. 12x -¹/²y¹/³=

x = 16 = 2^4
y = 64 = 2^6

a•
(2x)^(1/5)
= (2 . 2^4)^(1/5)
= (2^5)^(1/5)
= 2^(5×1/5)
= 2^1
= 2

b•
12x^(-1/2) y^(1/3)
= (2^2 × 3)(2^4)^(-1/2) . (2^6)^(1/3)
= 3 × 2^2 × 2^(4×-1/2) . 2^(6×1/3)
= 3 × 2^2 × 2^-2 × 2^2
= 3 × 2^(2-2+2)
= 3 × 2^2
= 12