pakai caranya ya kak? persamaan nilai mutlak linear satu variabel 1. [×+4] + [3×-2] = 6 2. [×-3] + [7-2×] =6 3. [×+2] + [3×] + [2×-5] =8

Penyelesaian :

1. [x + 4] + [3x - 2] = 6
    4x + 2= 6
    4x = 4
    x = 4.

2. [x - 3] + [7 - 2x] = 6
    x + 4 = 6
    x = 2.

3. [x + 2] + 3x + [2x - 5] = 8
    6x + 3 = 8
    6x = 5
    x = 5/6

Salam Alaikum.

1. [x+4] + [3x-2] = 6
x+3x + 4-2 = 6
4x + 2 = 6
4x = 4
x = 1
2. x - 2x + 7-3 = 6
-x + 4 =6
-x = 2
x = -2
3. x + 3x + 2x + 2-5 =8
6x - 3 = 8
6x = 11
x = 11/6