Nilai limit dari lim x=>0 4cosx sinx per tan 5x adalah

semoga membantu yaa :)

[tex] \lim_{x \to \ 0} \frac{4cosxsinx}{tan5x} \\ \lim_{x \to \ 0} \frac{4(1-2 sin^{2} \frac{1}{2}x)sinx }{tan5x} \\ \lim_{x \to \ 0} \frac{4sinx-8 sin^{2} \frac{1}{2}x.sinx }{tan5x} \\ \lim_{x \to \ 0} \frac{4x-8. \frac{1}{4} x^{2}.x }{5x} \\ \lim_{x \to \ 0} \frac{4-2 x^{2} }{5} = \frac{4-2 (0)^{2} }{5} = \frac{4}{5} [/tex]