pakai caranya ya?? persamaan nilai mutlak satu variabel 1. [7×-4]=3 2. [×]+[×+3]=5 3. [×-2]+[×+4]=7 4. [3×+1]+[2×-3]=5
Matematika
meda2
Pertanyaan
pakai caranya ya?? persamaan nilai mutlak satu variabel
1. [7×-4]=3
2. [×]+[×+3]=5
3. [×-2]+[×+4]=7
4. [3×+1]+[2×-3]=5
1. [7×-4]=3
2. [×]+[×+3]=5
3. [×-2]+[×+4]=7
4. [3×+1]+[2×-3]=5
1 Jawaban
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1. Jawaban Warda181
1. [7x - 4] = 3
7x = 3 + 4
7x = 7
x = 7/7
x = 1
2. [x] + [x+3] = 5
x + x = 5-3
2x = 2
x = 2/2
x = 1
3. [x+2] + [x+4] = 7
x + x = 7-4-2
2x = 1
x = 2/1
x = 2
4. [3x + 1] + [2x - 3] = 5
3x + 2x = 5 + 3 - 1
5x = 7
x = 7/5
x = 1,4