Berapakah Tb dan Tf larutan 0,1 mol barium nitrat dalam 500 gram air

Tb air = 100°C
Tf air = 0°C
Kb air = 0,52
Kf air = 1,86

molalitas
= mol x 1000/gr air
= 0,1 x (1000/500)
= 0,1 x 2
= 0,2 molal

ΔTb = kb x m
ΔTb = 0,52 x 0,2
ΔTb = 0,104°C

Tb larutan = 100 + 0,104 = 100,104°C

ΔTf = Kf x m
ΔTf = 1,86 x 0,2
ΔTf = 0,372°C

Tf larutan = 0° - 0,372 = - 0,372°C