tentukan suku pertama rasio dan suku ke 10 dan deret geometri berikut ini A.2,4,8 B.3,9,27 C.3,1,1/3

Bagian A
U1 = 2
r = U2/U1
= 4/2
= 2
U10 = ar^n-1
= 2 × 2^10-1
= 2 × 2^9
= 1.024

Bagian B
U1 = 3
r = 9/3 = 3
U10 = 3 × 3^10-1
= 3 × 3^9
= 59049

Bagian C
U1 = 3
r = 1/3
U10 = 3 × 1/3^10-1
= 3 × 1/3^9
= 1/3^8
= 1/6561