f''(x) = 12x - 4 , f' (-1) = 3 , dan f (2) = 5 tentukan rumus untuk fungsi f(x)

INteGRaL

F"(x) = 12x - 4
•
F'(x) = ∫F"(x) dx
F'(x) = ∫(12x - 4) dx
F'(x) = 6x² - 4x + C

F'(-1) = 3
6.(-1)² - 4(-1) + C = 3
6 + 4 + C = 3
C = -7
➡ F'(x) = 6x² - 4x - 7

•
F(x) = ∫F'(x) dx
F(x) = ∫(6x² - 4x - 7) dx
F(x) = 2x³ - 2x² - 7x + C

F(2) = 5
2.2³ - 2.2² - 7.2 + C = 5
16 - 8 - 14 + C = 5
C = 11

➡ F(x) = 2x³ - 2x² - 7x + 11