1) ^4 log 2√2 - ^2√3 log1/144 2) 2 ^9log27 - ^8 log 16 - 3 ^25 logg 5 Mohon bantuannya Jawab dengan cara
Matematika
permatapu3maharani
Pertanyaan
1) ^4 log 2√2 - ^2√3 log1/144
2) 2 ^9log27 - ^8 log 16 - 3 ^25 logg 5
Mohon bantuannya
Jawab dengan cara
2) 2 ^9log27 - ^8 log 16 - 3 ^25 logg 5
Mohon bantuannya
Jawab dengan cara
2 Jawaban
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1. Jawaban dnnyz07
Logaritma
^4 log 2√2 - ^2√3 log (1/144)
= (^(2^2) log √8 ) - ^√12 log (1/12²)
= (^(2^2) log (8)^(1/2)) - ^(12^(1/2)) log (12^-2)
= ( ^(2^2) log 2^(3/2)) - (-2/(1/2)) . ^12log 12
= ((3/2)/2 ) . ²log2 + 4
= 3/4 +4
= 19/4
2)
2 . ^9 log 27 - ^8 log 16 - 3 . ^25 log 5
= 2 . ^(3²) log 3³ - ^(2^3) log(2^4) - 3 . ^(5²) log (5¹)
= 2 . 3/2 . ³log 3 - 4/3 . ²log 2 - 3 . 1/2 . ^5 log 5
= 3 - 4/3 - 3/2
= 18/6 - 8/6 - 9/6
= 1/6 -