Matematika

Pertanyaan

1) ^4 log 2√2 - ^2√3 log1/144
2) 2 ^9log27 - ^8 log 16 - 3 ^25 logg 5

Mohon bantuannya
Jawab dengan cara

2 Jawaban

  • Logaritma


    ^4 log 2√2 - ^2√3 log (1/144)
    = (^(2^2) log √8 ) - ^√12 log (1/12²)
    = (^(2^2) log (8)^(1/2)) - ^(12^(1/2)) log (12^-2)
    = ( ^(2^2) log 2^(3/2)) - (-2/(1/2)) . ^12log 12
    = ((3/2)/2 ) . ²log2 + 4
    = 3/4 +4
    = 19/4


    2)

    2 . ^9 log 27 - ^8 log 16 - 3 . ^25 log 5
    = 2 . ^(3²) log 3³ - ^(2^3) log(2^4) - 3 . ^(5²) log (5¹)

    = 2 . 3/2 . ³log 3 - 4/3 . ²log 2 - 3 . 1/2 . ^5 log 5
    = 3 - 4/3 - 3/2
    = 18/6 - 8/6 - 9/6
    = 1/6
  • semoga membantu yaa :)
    Gambar lampiran jawaban idznizhahrina

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