4(32 ¹/5)x6(27 -¹/3)
Matematika
ampyang
Pertanyaan
4(32 ¹/5)x6(27 -¹/3)
1 Jawaban
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1. Jawaban Anonyme
4(32^(1/5)) × 6(27^(-1/3))
= (2^2)(2^(5×1/5)) × (2 × 3)(3^(3×-1/3))
= 2^3 × 2
= 2^4
= 16